1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 | #!/usr/local/bin/expect -f # Password change shell script, tested on Linux and FreeBSD # ---------------------------------- # It need expect tool. If you are using Linux use following command # to install expect # apt-get install expect # FreeBSD user can use ports or following command: # pkg_add -r -v expect # ---------------------------------- # If you are using linux change first line # From: #!/usr/local/bin/expect -f # To: #!/usr/bin/expect -f # ----------------------------------------------- # Copyright (c) 2006 nixCraft project # This script is licensed under GNU GPL version 2.0 or above # ------------------------------------------------------------------------- # This script is part of nixCraft shell script collection (NSSC) # Visit http://bash.cyberciti.biz/ for more information. # ------------------------------------------------------------------------- # display usage if {$argc!=2} { send_user "usage: $argv0 username password \n" exit } # script must be run by root user set whoami [exec id -u] if {$whoami!=0} { send_user "You must be a root user to run this script\n" exit } # set timeout -1 match_max 100000 # stopre password set password [lindex $argv 1] # username set user [lindex $argv 0] # opem shell spawn $env(SHELL) # send passwd command send -- "passwd $user\r" expect "assword:" send "$password\r" expect "assword:" send "$password\r" send "\r" expect eof |
Hi,
best would be to edit the script:
to
The script is universally usable after that change. Otherwise the script wont run for german e.g. I edited, and it works perfectly for ubuntu.
Edited by Admin: Added pre tags to the code.
chage -d 1 user_name —> with this you need to change your password every day force by the root-
Without „set timeout -1“ this script working well, you have just to wait some seconds.
Ok, I’m trying to create a script that crontab will run every day that changes root pass to a random 20 digit string. (obxnux, I think we’re wanting something similar) I have tried chpasswd, but it doesn’t work, sets root pwd to nill. (don’t worry, I’ve rectified that before this post) My script’s at the end, what am I doing wrong??
#!/bin/bash
iam=$(whoami)
pass=> /root/pass
cat /root/pass | chpasswd
rm -f /root/pass
else
sudo echo root:$pass >> /root/pass
sudo cat /root/pass | chpasswd
sudo rm -f /root/pass
fi
exit 0 #the only way you should ever exit script
THAT is not my script?? Lemme try again…
#!/bin/bash
iam=$(whoami)
pass=> /root/pass
cat /root/pass | chpasswd
rm -f /root/pass
else
sudo echo root:$pass >> /root/pass
sudo cat /root/pass | chpasswd
sudo rm -f /root/pass
fi
exit 0
I’m begining to think there’s something wrong here, under the “iam” line is supposed to be one that assigns a random 20 digit phrase to $pass?? why won’t it post correctly?
#!/bin/bash
iam=$(whoami)
pass=> /root/pass
cat /root/pass | chpasswd
rm -f /root/pass
else
sudo echo root:$pass >> /root/pass
sudo cat /root/pass | chpasswd
sudo rm -f /root/pass
fi
exit 0
Hi, I would like to know how can I make a script for change root password using crontab. Thank you
Fred,
so executing history -c at the end would not help? Checked on my machine and it works.
All of these are bad ideas. You do not want your password being processed via the shell. Most shells keep a history file of commands executed – and this will show up in them. In general, you do not want your password saved in cleartext anywhere, regardless of file system controls.
The password command doesn’t store the information in clear text. Running a history command will not return with:
17: passwd 123456
The user can’t even see if they’re typing in the password correctly so really the only way someone could get the password is if they were watching you type it in and you were a somewhat slow and “distinguished” typist.
chpasswd is your friend:
echo username:password | chpasswd
You can even do
cat passlist.txt | chpasswd
where passlist.txt is a newline delimited list of username:password pairs.
Thanks!!
Worked for me.
THANKS ! WORKS HERE 2
Epic Win!!!
Works here 3
Thanx
Doesnt work here 1 :(
It gave the following error :
echo one:different | chpasswd ( “one” is username & “different” is the new password i wish to give it )
Changing password for one.
chpasswd: (user one) pam_chauthtok() failed, error:
Authentication token manipulation error
chpasswd: (line 1, user one) password not changed
Pls help ….
Um, yea Tamilan – that doesn’t actually work. Did you try it yourself? All it does on my machine is remove a shell from the test user and not change the password.
The problem I’m running into with the above script is that it isn’t properly returning to the cli when done. In fact it is a pain in the ass to run within another script.
Long story short.
echo $password | /usr/bin/passwd –stdin user1