This script uses sed command to find out all digits or upper characters. -z string (conditional expression) will return true if the length of string is zero.
Script logic
Read one character
[1] Use sed command to determine input character is digit or not (sed -e ‘s/[A-Z]//g’))
If digits are in input, it will replace all those digit, and if input is only digit, nothing is left i.e. string is zero and that is what tasted with -z conditional expression.
#!/bin/bash # Shell script to read a character (upper or lower), digit, special symbol and # display message according to the character entered # ----------------------------------------------- # Copyright (c) 2005 nixCraft project <http://cyberciti.biz/fb/> # This script is licensed under GNU GPL version 2.0 or above # ------------------------------------------------------------------------- # This script is part of nixCraft shell script collection (NSSC) # Visit http://bash.cyberciti.biz/ for more information. # ------------------------------------------------------------------------- char="" echo -n "Enter a one character : " read char # use sed command to determine input character is digit or not # -e : start script # s/[0-9]// : Attempt to match regex [0-9] i.e. all digit against the pattern space (echo $char). # If successful, replace that portion matched with replacement i.e. // do nothing. # g : Global replacement # so if digit are in input it will replace all those digit, and if input is only digit, nothing # is left i.e. string is zero and that is what tasted with -z if [ -z $(echo $char | sed -e 's/[0-9]//g') ] then echo "$char is Number/digit" elif [ -z $(echo $char | sed -e 's/[A-Z]//g') ] # find out if character is upper then echo "$char is UPPER character" elif [ -z $(echo $char | sed -e 's/[a-z]//g') ] # find out if character is lower then echo "$char is lower character" else echo "$char is Special symbol" # else it is special character fi
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Please can u make only one command to check number and alphabet
Here’s a way to do the same thing in pure bash (no sed) and in half the lines. More info here: https://www.gnu.org/software/bash/manual/html_node/Pattern-Matching.html and here: https://www.gnu.org/software/bash/manual/html_node/Conditional-Constructs.html.
#!/bin/bash read -p "Enter a one character : " char case $char in [[:digit:]]) echo "$char is Number/digit" ;; [[:upper:]]) echo "$char is UPPER character" ;; [[:lower:]]) echo "$char is lower character" ;; *) echo "$char is Special symbol" ;; esacHI!
Here i want replace /leftarrow with leftarrow in my html file. Below one is my code. But its not working properly. Please help !!!
#!/bin/bash
# ALL HTML FILES
FILES=”*.html”
# for loop read each file
for f in $FILES
do
INF=”$f”
OUTF=”$f.out.tmp”
sed ‘s/[/leftarrow]/leftarrow/g’ $INF > $OUTF
/bin/cp $OUTF $INF
/bin/rm -f $OUTF
done
Thanks in advance
sed ’s/[/leftarrow]/leftarrow/g’ $INF > $OUTF —- in this line use as below
sed ’s/ \ /leftarrow/leftarrow/g’ $INF > $OUTF— “\” is the escape sequence
FYI, you can use “sed -i” so that you won’t have to copy the input to output and remove the file…
hi
how to detect the occurance of any character and further save it on onother file using shell script.
say i have smb.conf file and i have to detect the occurance of “[” and “]” and save all words enclosed in this brackets..
I hope u understand my problem thanks…
Hi,
how can you detect if the character is a NULL ?