15 comment

1. I don’t understand the part
   – eq0
   In finding odd and even number

   1. -eq is a symbolof equal and 0 represent rem is zero

2. how to check the entered number is grater than 10

3. I want to find even and odd number (1 to n) using loop

4. echo “enter the number”
   read n

   2num=$(( $n % 2 ))
   if [ $num -eq 0 ]

   then
   echo “$n number is even”
   else
   echo “$n number is odd”
   fi

5. read n
   n2=expr $n % 2
   if [ $n2 -eq 0 ];
   then
   echo “even”
   else
   echo “odd”
   fi

6. echo “Program to check even or odd number”
   echo “Enter a number”
   read n
   a=expr $n % 2
   if [ $a -eq 0 ] ; then #Semicolon is most important for Executing if-else
   echo “It is an even number”
   else
   echo “It is an odd number”
   fi

7. if[ $($n % 2) -eq 0]
   then
   echo “even”
   else
   echo “odd”

   1. nevermind

8. odd() { let ${1: -1}%2 && return 0; return 1; }

9. is_even() {
   case $(( 10#$1 % 2 )) in
   0) return 0 ;;
   *) return 1 ;;
   esac
   }

10. correct it as:
    if [ $rem -eq ‘0’ ]

11. @Aakash Alfred: No buddy, that doesn’t work. It displays everything as odd……..

12. # On the third line: Instead of rem=$(( $n % 2 ))
    # You can use ;
    rem= expr $n % 2

    1. $(( $n % 2 ))
       this syntax not work properly in shell script
       error in brackets

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