#!/bin/bash # Shell program to read a number and reverse the number # for example 123 should output as 321 # ----------------------------------------------- # Copyright (c) 2005 nixCraft project <http://cyberciti.biz/fb/> # This script is licensed under GNU GPL version 2.0 or above # ------------------------------------------------------------------------- # This script is part of nixCraft shell script collection (NSSC) # Visit http://bash.cyberciti.biz/ for more information. # ------------------------------------------------------------------------- echo -n "Enter number : " read n # store single digit sd=0 # store number in reverse order rev="" # store original number on=$n # use while loop to caclulate the sum of all digits while [ $n -gt 0 ] do sd=$(( $n % 10 )) # get Remainder n=$(( $n / 10 )) # get next digit # store previoues number and current digit in rev rev=$( echo ${rev}${sd} ) done echo "$on in a reverse order $rev"
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it worked for me…..but I want to use a function,what change should i make here
iq154
if the cond is [ $n -ne 0 ] den it will work for negative integers
Hey gd bt will not work for negetive number ….
nice explain…….
there is a flaw in your program
if i enter 004
the output should be 400
but instead it gives 4 ?!
how will you correct this
it is good, but straight forward, there must be some different logic.
nice explaination
yeah, it was good
it was good