12 comment

1. #!/bin/bash
### Script to count vowels, no.of lines,blank spaces, words in a given file
echo " Enter the file name "
read a
char=cat $a | wc -m
   echo "The number of characters in file are:" $char
   line=cat $a | wc -l
   echo "The number of lines are:" $line
   vow=cat $a | grep -o "[aAeEiIoOuU]" |wc -l
   echo "The number of vowels are:" $vow
   space=cat $a | grep -o " "| wc -l
   echo "The number of blank spaces are:" $space

2. i used grep command but it give wrong output .. count vowel and consonant in file
   i think i search only for one time

3. no need for the loop in counting vowels…

   grep -o “[AEIOUaeiou]” $file|wc -l

   …will do the trick

4. I need to count number blank records for particular column.

   total record in a file is 100
   total blank in column1 is 40 or so.

   How to get this?

   Thanks in advance
   Umar

5. why was “exec 3<&0" added to the above script..
   I mean what's its use??

6. Hello,
   give me a suggestion to
   print the word containing vowel

7. Hello Aswin Triadhi

   you can easily replace the word with sed using the following command

   sed ‘s/stopped/idle/g’
   this will replace the word globally…

8. Halo viviek

   How to replace a word in file text
   I have printers.conf in /var/cups/printers.conf
   and I want replace the State Stopped to State Idle with shell script
   example

   Info MY_PRINT
   DeviceURI hp:/net/hp_LaserJet_4250?ip=88.8.8.223
   State Stopped
   StateTime 1254732779
   Accepting Yes
   Shared Yes
   JobSheets none none
   QuotaPeriod 0
   PageLimit 0
   KLimit 0
   OpPolicy default
   ErrorPolicy stop-printer

   I want replace the State Stopped with State Idle, how ?
   regards

9. what is 3<&0?

10. Man you need to add;
    ı
    ö
    ü
    for vowels too.
    Thank you for script.

11. Vivek, always learn something on your site..thanks

    btw:
    echo “Vowles : $v” (sic) “Vowels”

    1. @Jim,

       Thanks for the heads up!

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