Shell Script To Delete Files In The First Directory Which Are Similarly Named In The Second Directory
Posted in Decision Making » File-management
A shell script to compare files in two directory and delete files in the first directory which are similarly named in the second directory. Following script uses for loop to compare files in a each directory.
#!/bin/bash # Write a shell script that accepts two directory names as arguments and # deletes those files in the first directory which are similarly named in # the second directory. SRC="$1" DST="$2" if [ $# -ne 2 ] then echo "$(basename $0) dir1 dir2" exit 1 fi if [ ! -d $SRC ] then echo "Directory $SRC does not exists!" exit 2 fi if [ ! -d $DST ] then echo "Directory $DST does not exists!" exit 2 fi for f in $DST/* do #echo Processing $f if [ -f $f ] then tFile="$SRC/$(basename $f)" if [ -f $tFile ] then echo -n "Deleting $tFile..." /bin/rm $tFile [ $? -eq 0 ] && echo "done" || echo "failed" fi fi done
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Tags: directory names, directory structure, exit status, for command, for loop, if command, loop method, search directory, shell loops ~ Last updated on: July 15, 2008
