Menu Driven Shell Script
Posted in Decision Making
Explains how to write a menu driven Shell script, which has following options:
1. Contents of /etc/passwd
2. List of users currently logged
3. Present handling directory (working directory)
4. Exit
Take action as per selected option
#!/bin/bash # A menu driven Shell script which has following options # Contents of /etc/passwd # List of users currently logged # Prsent handling directory # Exit # As per option do the job # ----------------------------------------------- # Copyright (c) 2005 nixCraft project <http://cyberciti.biz/fb/> # This script is licensed under GNU GPL version 2.0 or above # ------------------------------------------------------------------------- # This script is part of nixCraft shell script collection (NSSC) # Visit http://bash.cyberciti.biz/ for more information. # ------------------------------------------------------------------------- while : do clear echo " M A I N - M E N U" echo "1. Contents of /etc/passwd" echo "2. List of users currently logged" echo "3. Prsent handling directory" echo "4. Exit" echo -n "Please enter option [1 - 4]" read opt case $opt in 1) echo "************ Conents of /etc/passwd *************"; more /etc/passwd;; 2) echo "*********** List of users currently logged"; who | more;; 3) echo "You are in $(pwd) directory"; echo "Press [enter] key to continue. . ."; read enterKey;; 4) echo "Bye $USER"; exit 1;; *) echo "$opt is an invaild option. Please select option between 1-4 only"; echo "Press [enter] key to continue. . ."; read enterKey;; esac done
Download - Email this to a friend - Printable version
Leave a Reply
We encourage your comments, and suggestions. But please stay on topic, be polite, and avoid spam. Thank you very much for stopping by our site!
Tags: case ... esac command, if command, main menu script, menu scripts, select option, selected option, shell loops, while loop ~ Last updated on: April 5, 2008
