Shell program to read a number and reverse the number
Posted in Academic » Shell Math
#!/bin/bash # Shell program to read a number and reverse the number # for example 123 should output as 321 # ----------------------------------------------- # Copyright (c) 2005 nixCraft project <http://cyberciti.biz/fb/> # This script is licensed under GNU GPL version 2.0 or above # ------------------------------------------------------------------------- # This script is part of nixCraft shell script collection (NSSC) # Visit http://bash.cyberciti.biz/ for more information. # ------------------------------------------------------------------------- echo -n "Enter number : " read n # store single digit sd=0 # store number in reverse order rev="" # store original number on=$n # use while loop to caclulate the sum of all digits while [ $n -gt 0 ] do sd=$(( $n % 10 )) # get Remainder n=$(( $n / 10 )) # get next digit # store previoues number and current digit in rev rev=$( echo ${rev}${sd} ) done echo "$on in a reverse order $rev"
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Tags: bash shell, digits, loop method, mathematics, remainder, shell loops, shell program, shell script, while loop ~ Last updated on: April 8, 2008
